Spontaneous Reaction

Question

For a spontaneous reaction the !!DeltaG!!, equilibrium constant!!(K)!! will be:

  • !!-ve,>1!!
  • !!-ve,<1!!
  • !!+ve,>1!!
  • !!+ve,<1!!

Solution

For a spontaneous reaction the change in gibbs free energy is negative.

!!DeltaG<0!!

Now we know that !!DeltaG=DeltaG^@-RTlnK!!, but when the reaction is in equilibrium !!DeltaG=0!!.

So we get that !!DeltaG^@=-RTlnK!!. For this question we are assuming that in the standard state the reaction is spontaneous so !!DeltaG^@<0!!.

Hence we get that !!lnK>0=>k>1!!

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