Motion in straight line

Question

A ball is dropping in 3 different ways

(a) X-i, Y- ii, Z-iii

(b) X-ii, Y-i, Z-iii

(c) X-ii, Y-iii, Z-i

(d) X-iii, Y-ii, Z-i

Solution

Simple concept steeper the path greater the velocity.

The starting slope for the ball in X is steepest. So, acceleration is more therefore slope of the graph v/t in the starting will be maximum. So, for X is ii.

Y and Z alomost identical, but for Z the section before the flat region is longer. So it is going to taken a longer to reach constant velocity. In graph iii we see that the time taken by the ball to reach constant velocity is higher. So, for Z the correct graph is iii. The remaining is for y

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