!! A -> !! Products [:Zero order]
!!B -> !! Products [:First order]
For what initial concentration of !!A!! are the half lives of two reactions equal? [Both have same rate of reaction]
a) !!(log_e 4)!!M
b) !!2!! M
c) !!2 log2!! M
d) !!ln2!! M
For zero order reaction,
Therefore, !!a/2 = kxxt_(1//2)!!
!!=> t_(1//2)= a/(2k)....(1)!!
For first order reaction,
!!t_(1//2)= (log_e 2)/k.......(2)!!
From equation !!(1)!! and !!(2)!!, we get
!! a/(2k)= (log_e 2)/k!! [given that]
!!=> a = 2log_e 2= log_e 4!!
Therefore, option (A)is correct.