Question

For a given reaction, t_(1//2)= 1/(ka^2). The order of this recation is:

(a) 2

(b) 3

(c) 1

(d) 0

Solution

The relationship between half life and initial concentration is given as:

t_(1/2) prop 1/(a\^(n-1))

Where n= order of reaction.

Here we have

t_(1/2) prop 1/(a^2)

Thus by comparing:

a\^(n-1)=a\^2

n-1=2

n=3

Hence it's a third order reaction.

Therefore option (b) is correct.